Base | Representation |
---|---|
bin | 1011110110101000000111… |
… | …1001100100100101000011 |
3 | 1201010221201212001100112012 |
4 | 2331222001321210211003 |
5 | 3202013302143111323 |
6 | 43415154513323135 |
7 | 2513416422142541 |
oct | 275520171444503 |
9 | 51127655040465 |
10 | 13033110128963 |
11 | 4175346993741 |
12 | 1565aa22664ab |
13 | 73702b4b39c2 |
14 | 330b3d542d91 |
15 | 17904b35a678 |
hex | bda81e64943 |
13033110128963 has 2 divisors, whose sum is σ = 13033110128964. Its totient is φ = 13033110128962.
The previous prime is 13033110128897. The next prime is 13033110128971. The reversal of 13033110128963 is 36982101133031.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13033110128963 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13033110128963.
It is not a weakly prime, because it can be changed into another prime (13033110128263) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6516555064481 + 6516555064482.
It is an arithmetic number, because the mean of its divisors is an integer number (6516555064482).
Almost surely, 213033110128963 is an apocalyptic number.
13033110128963 is a deficient number, since it is larger than the sum of its proper divisors (1).
13033110128963 is an equidigital number, since it uses as much as digits as its factorization.
13033110128963 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 69984, while the sum is 41.
The spelling of 13033110128963 in words is "thirteen trillion, thirty-three billion, one hundred ten million, one hundred twenty-eight thousand, nine hundred sixty-three".
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