Base | Representation |
---|---|
bin | 11101101000100101001001… |
… | …010011011111011001101101 |
3 | 122002110121201000222221001001 |
4 | 131220211021103133121231 |
5 | 114040324430141140440 |
6 | 1141105411104520301 |
7 | 36311114524001344 |
oct | 3550451123373155 |
9 | 562417630887031 |
10 | 130332012443245 |
11 | 38589550303998 |
12 | 1274b273320091 |
13 | 579534368bbb2 |
14 | 2428162b22b5b |
15 | 101037c3a0b9a |
hex | 7689494df66d |
130332012443245 has 32 divisors (see below), whose sum is σ = 160009489463040. Its totient is φ = 101879626314240.
The previous prime is 130332012443231. The next prime is 130332012443251. The reversal of 130332012443245 is 542344210233031.
It is a de Polignac number, because none of the positive numbers 2k-130332012443245 is a prime.
It is a super-2 number, since 2×1303320124432452 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1244036665 + ... + 1244141425.
It is an arithmetic number, because the mean of its divisors is an integer number (5000296545720).
Almost surely, 2130332012443245 is an apocalyptic number.
It is an amenable number.
130332012443245 is a deficient number, since it is larger than the sum of its proper divisors (29677477019795).
130332012443245 is a wasteful number, since it uses less digits than its factorization.
130332012443245 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 130245.
The product of its (nonzero) digits is 207360, while the sum is 37.
Adding to 130332012443245 its reverse (542344210233031), we get a palindrome (672676222676276).
The spelling of 130332012443245 in words is "one hundred thirty trillion, three hundred thirty-two billion, twelve million, four hundred forty-three thousand, two hundred forty-five".
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