Base | Representation |
---|---|
bin | 1011110110101000100100… |
… | …0011010011010001011111 |
3 | 1201010222001012211112022211 |
4 | 2331222021003103101133 |
5 | 3202014023402320111 |
6 | 43415214441221251 |
7 | 2513422410065662 |
oct | 275521103232137 |
9 | 51128035745284 |
10 | 13033230120031 |
11 | 41753a8699810 |
12 | 1565b16491827 |
13 | 73704a306834 |
14 | 330b514596d9 |
15 | 179056b5d521 |
hex | bda890d345f |
13033230120031 has 4 divisors (see below), whose sum is σ = 14218069221864. Its totient is φ = 11848391018200.
The previous prime is 13033230120007. The next prime is 13033230120037. The reversal of 13033230120031 is 13002103233031.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 13033230120031 - 211 = 13033230117983 is a prime.
It is a super-2 number, since 2×130332301200312 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13033230119984 and 13033230120011.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13033230120037) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 592419550900 + ... + 592419550921.
It is an arithmetic number, because the mean of its divisors is an integer number (3554517305466).
Almost surely, 213033230120031 is an apocalyptic number.
13033230120031 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
13033230120031 is a deficient number, since it is larger than the sum of its proper divisors (1184839101833).
13033230120031 is a wasteful number, since it uses less digits than its factorization.
13033230120031 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1184839101832.
The product of its (nonzero) digits is 972, while the sum is 22.
Adding to 13033230120031 its reverse (13002103233031), we get a palindrome (26035333353062).
The spelling of 13033230120031 in words is "thirteen trillion, thirty-three billion, two hundred thirty million, one hundred twenty thousand, thirty-one".
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