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130332420255 = 358688828017
BaseRepresentation
bin111100101100001101…
…0101110100010011111
3110110102002102221111010
41321120122232202133
54113410044422010
6135512432030303
712262521202422
oct1713032564237
9413362387433
10130332420255
1150301287414
1221314092393
13c3a0a140cb
1464456bb9b9
1535cc128620
hex1e586ae89f

130332420255 has 8 divisors (see below), whose sum is σ = 208531872432. Its totient is φ = 69510624128.

The previous prime is 130332420247. The next prime is 130332420259. The reversal of 130332420255 is 552024233031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 130332420255 - 23 = 130332420247 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130332420259) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4344413994 + ... + 4344414023.

It is an arithmetic number, because the mean of its divisors is an integer number (26066484054).

Almost surely, 2130332420255 is an apocalyptic number.

130332420255 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

130332420255 is a deficient number, since it is larger than the sum of its proper divisors (78199452177).

130332420255 is an equidigital number, since it uses as much as digits as its factorization.

130332420255 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8688828025.

The product of its (nonzero) digits is 21600, while the sum is 30.

Adding to 130332420255 its reverse (552024233031), we get a palindrome (682356653286).

The spelling of 130332420255 in words is "one hundred thirty billion, three hundred thirty-two million, four hundred twenty thousand, two hundred fifty-five".

Divisors: 1 3 5 15 8688828017 26066484051 43444140085 130332420255