Base | Representation |
---|---|
bin | 1011110110101000110101… |
… | …0101100111011111110011 |
3 | 1201010222020020010221200222 |
4 | 2331222031111213133303 |
5 | 3202014200304432243 |
6 | 43415225530403255 |
7 | 2513424242236661 |
oct | 275521525473763 |
9 | 51128206127628 |
10 | 13033302030323 |
11 | 4175435245003 |
12 | 1565b3659052b |
13 | 73705c1939c3 |
14 | 330b5ac17c31 |
15 | 17905d115168 |
hex | bda8d5677f3 |
13033302030323 has 2 divisors, whose sum is σ = 13033302030324. Its totient is φ = 13033302030322.
The previous prime is 13033302030319. The next prime is 13033302030367. The reversal of 13033302030323 is 32303020333031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13033302030323 - 22 = 13033302030319 is a prime.
It is a super-2 number, since 2×130333020303232 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13033302030292 and 13033302030301.
It is not a weakly prime, because it can be changed into another prime (13033302030313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6516651015161 + 6516651015162.
It is an arithmetic number, because the mean of its divisors is an integer number (6516651015162).
Almost surely, 213033302030323 is an apocalyptic number.
13033302030323 is a deficient number, since it is larger than the sum of its proper divisors (1).
13033302030323 is an equidigital number, since it uses as much as digits as its factorization.
13033302030323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8748, while the sum is 26.
Adding to 13033302030323 its reverse (32303020333031), we get a palindrome (45336322363354).
The spelling of 13033302030323 in words is "thirteen trillion, thirty-three billion, three hundred two million, thirty thousand, three hundred twenty-three".
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