Base | Representation |
---|---|
bin | 10010111101110100101… |
… | …010100101011111000011 |
3 | 11121121010110212111012001 |
4 | 102331310222211133003 |
5 | 132323211044130311 |
6 | 2434424224444431 |
7 | 163106535464326 |
oct | 22756452453703 |
9 | 4547113774161 |
10 | 1303332411331 |
11 | 462816194145 |
12 | 190717479717 |
13 | 95b99617172 |
14 | 4711dda07bd |
15 | 23d8177b4c1 |
hex | 12f74aa57c3 |
1303332411331 has 2 divisors, whose sum is σ = 1303332411332. Its totient is φ = 1303332411330.
The previous prime is 1303332411247. The next prime is 1303332411343. The reversal of 1303332411331 is 1331142333031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1303332411331 - 221 = 1303330314179 is a prime.
It is a super-2 number, since 2×13033324113312 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1303332411331.
It is not a weakly prime, because it can be changed into another prime (1303332411131) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651666205665 + 651666205666.
It is an arithmetic number, because the mean of its divisors is an integer number (651666205666).
Almost surely, 21303332411331 is an apocalyptic number.
1303332411331 is a deficient number, since it is larger than the sum of its proper divisors (1).
1303332411331 is an equidigital number, since it uses as much as digits as its factorization.
1303332411331 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5832, while the sum is 28.
Adding to 1303332411331 its reverse (1331142333031), we get a palindrome (2634474744362).
The spelling of 1303332411331 in words is "one trillion, three hundred three billion, three hundred thirty-two million, four hundred eleven thousand, three hundred thirty-one".
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