Base | Representation |
---|---|
bin | 10010111101110101111… |
… | …100111100101011010011 |
3 | 11121121011222111102012022 |
4 | 102331311330330223103 |
5 | 132323232111032011 |
6 | 2434430315322055 |
7 | 163110220140266 |
oct | 22756574745323 |
9 | 4547158442168 |
10 | 1303354002131 |
11 | 4628273a0685 |
12 | 19072275032b |
13 | 95ba0c3669c |
14 | 47122bc0cdd |
15 | 23d835e38db |
hex | 12f75f3cad3 |
1303354002131 has 2 divisors, whose sum is σ = 1303354002132. Its totient is φ = 1303354002130.
The previous prime is 1303354002101. The next prime is 1303354002193. The reversal of 1303354002131 is 1312004533031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1303354002131 - 226 = 1303286893267 is a prime.
It is a super-2 number, since 2×13033540021312 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1303354002131.
It is not a weakly prime, because it can be changed into another prime (1303354002101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651677001065 + 651677001066.
It is an arithmetic number, because the mean of its divisors is an integer number (651677001066).
Almost surely, 21303354002131 is an apocalyptic number.
1303354002131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1303354002131 is an equidigital number, since it uses as much as digits as its factorization.
1303354002131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3240, while the sum is 26.
Adding to 1303354002131 its reverse (1312004533031), we get a palindrome (2615358535162).
The spelling of 1303354002131 in words is "one trillion, three hundred three billion, three hundred fifty-four million, two thousand, one hundred thirty-one".
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