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130340052555 = 3517511137461
BaseRepresentation
bin111100101100011011…
…1110101111001001011
3110110102121210201000220
41321120313311321023
54113414023140210
6135513303401123
712262643111136
oct1713067657113
9413377721026
10130340052555
115030561a6a9
12213167531a3
13c3a248706b
14644670721d
1535ccb34c70
hex1e58df5e4b

130340052555 has 16 divisors (see below), whose sum is σ = 220811383584. Its totient is φ = 65425594880.

The previous prime is 130340052533. The next prime is 130340052581. The reversal of 130340052555 is 555250043031.

It is a happy number.

It is not a de Polignac number, because 130340052555 - 28 = 130340052299 is a prime.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 255568476 + ... + 255568985.

It is an arithmetic number, because the mean of its divisors is an integer number (13800711474).

Almost surely, 2130340052555 is an apocalyptic number.

130340052555 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

130340052555 is a deficient number, since it is larger than the sum of its proper divisors (90471331029).

130340052555 is a wasteful number, since it uses less digits than its factorization.

130340052555 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 511137486.

The product of its (nonzero) digits is 45000, while the sum is 33.

Adding to 130340052555 its reverse (555250043031), we get a palindrome (685590095586).

The spelling of 130340052555 in words is "one hundred thirty billion, three hundred forty million, fifty-two thousand, five hundred fifty-five".

Divisors: 1 3 5 15 17 51 85 255 511137461 1533412383 2555687305 7667061915 8689336837 26068010511 43446684185 130340052555