Base | Representation |
---|---|
bin | 11101101000101100110010… |
… | …010010000111101010011011 |
3 | 122002111101212202201000202212 |
4 | 131220230302102013222123 |
5 | 114040443230313024431 |
6 | 1141113245122345335 |
7 | 36311525030204015 |
oct | 3550546222075233 |
9 | 562441782630685 |
10 | 130340216142491 |
11 | 38591a80060623 |
12 | 127509827bb24b |
13 | 5796050182cc4 |
14 | 24287004931b5 |
15 | 10106ac6d672b |
hex | 768b32487a9b |
130340216142491 has 2 divisors, whose sum is σ = 130340216142492. Its totient is φ = 130340216142490.
The previous prime is 130340216142469. The next prime is 130340216142511. The reversal of 130340216142491 is 194241612043031.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130340216142491 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (130340216142091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65170108071245 + 65170108071246.
It is an arithmetic number, because the mean of its divisors is an integer number (65170108071246).
Almost surely, 2130340216142491 is an apocalyptic number.
130340216142491 is a deficient number, since it is larger than the sum of its proper divisors (1).
130340216142491 is an equidigital number, since it uses as much as digits as its factorization.
130340216142491 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 124416, while the sum is 41.
The spelling of 130340216142491 in words is "one hundred thirty trillion, three hundred forty billion, two hundred sixteen million, one hundred forty-two thousand, four hundred ninety-one".
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