13034031433 has 4 divisors (see below), whose sum is σ = 13254947280. Its totient is φ = 12813115588.

The previous prime is 13034031431. The next prime is 13034031509. The reversal of 13034031433 is 33413043031.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13034031433 - 2¹ = 13034031431 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13034031398 and 13034031407.

It is not an unprimeable number, because it can be changed into a prime (13034031431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 110457835 + ... + 110457952.

It is an arithmetic number, because the mean of its divisors is an integer number (3313736820).

Almost surely, 2^13034031433 is an apocalyptic number.

It is an amenable number.

13034031433 is a deficient number, since it is larger than the sum of its proper divisors (220915847).

13034031433 is an equidigital number, since it uses as much as digits as its factorization.

13034031433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 220915846.

The product of its (nonzero) digits is 3888, while the sum is 25.

Adding to 13034031433 its reverse (33413043031), we get a palindrome (46447074464).

The spelling of 13034031433 in words is "thirteen billion, thirty-four million, thirty-one thousand, four hundred thirty-three".