13034115141 has 4 divisors (see below), whose sum is σ = 17378820192. Its totient is φ = 8689410092.

The previous prime is 13034115139. The next prime is 13034115161. The reversal of 13034115141 is 14151143031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14151143031 = 3 ⋅4717047677.

It is a cyclic number.

It is not a de Polignac number, because 13034115141 - 2¹ = 13034115139 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13034115161) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2172352521 + ... + 2172352526.

It is an arithmetic number, because the mean of its divisors is an integer number (4344705048).

Almost surely, 2^13034115141 is an apocalyptic number.

It is an amenable number.

13034115141 is a deficient number, since it is larger than the sum of its proper divisors (4344705051).

13034115141 is an equidigital number, since it uses as much as digits as its factorization.

13034115141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4344705050.

The product of its (nonzero) digits is 720, while the sum is 24.

Adding to 13034115141 its reverse (14151143031), we get a palindrome (27185258172).

The spelling of 13034115141 in words is "thirteen billion, thirty-four million, one hundred fifteen thousand, one hundred forty-one".