Base | Representation |
---|---|
bin | 11000010001110010… |
… | …01110110100100111 |
3 | 1020122101000000210002 |
4 | 30020321032310213 |
5 | 203143213410120 |
6 | 5553210251515 |
7 | 640666133150 |
oct | 141071166447 |
9 | 36571000702 |
10 | 13034122535 |
11 | 55894711a5 |
12 | 2639126b9b |
13 | 12c948b255 |
14 | 8b90cc927 |
15 | 514442375 |
hex | 308e4ed27 |
13034122535 has 16 divisors (see below), whose sum is σ = 18076219200. Its totient is φ = 8837258496.
The previous prime is 13034122523. The next prime is 13034122553. The reversal of 13034122535 is 53522143031.
It is a happy number.
13034122535 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 13034122535 - 28 = 13034122279 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13034122498 and 13034122507.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2089040 + ... + 2095269.
It is an arithmetic number, because the mean of its divisors is an integer number (1129763700).
Almost surely, 213034122535 is an apocalyptic number.
13034122535 is a deficient number, since it is larger than the sum of its proper divisors (5042096665).
13034122535 is an equidigital number, since it uses as much as digits as its factorization.
13034122535 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4184410.
The product of its (nonzero) digits is 10800, while the sum is 29.
Adding to 13034122535 its reverse (53522143031), we get a palindrome (66556265566).
The spelling of 13034122535 in words is "thirteen billion, thirty-four million, one hundred twenty-two thousand, five hundred thirty-five".
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