Base | Representation |
---|---|
bin | 11101101000110110110111… |
… | …101011010011110100100111 |
3 | 122002112102211101022201210021 |
4 | 131220312313223103310213 |
5 | 114041132414234101330 |
6 | 1141122235402140011 |
7 | 36312360246665062 |
oct | 3550666753236447 |
9 | 562472741281707 |
10 | 130351044050215 |
11 | 3859662713799a |
12 | 12752aa4ab1607 |
13 | 5797087544bb1 |
14 | 242904a5678d9 |
15 | 1010ae30d067a |
hex | 768db7ad3d27 |
130351044050215 has 4 divisors (see below), whose sum is σ = 156421252860264. Its totient is φ = 104280835240168.
The previous prime is 130351044050177. The next prime is 130351044050363. The reversal of 130351044050215 is 512050440153031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 130351044050215 - 29 = 130351044049703 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13035104405017 + ... + 13035104405026.
It is an arithmetic number, because the mean of its divisors is an integer number (39105313215066).
Almost surely, 2130351044050215 is an apocalyptic number.
130351044050215 is a deficient number, since it is larger than the sum of its proper divisors (26070208810049).
130351044050215 is an equidigital number, since it uses as much as digits as its factorization.
130351044050215 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 26070208810048.
The product of its (nonzero) digits is 36000, while the sum is 34.
The spelling of 130351044050215 in words is "one hundred thirty trillion, three hundred fifty-one billion, forty-four million, fifty thousand, two hundred fifteen".
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