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130352500311 = 31121670321499
BaseRepresentation
bin111100101100110011…
…1010100111001010111
3110110110111020010010220
41321121213110321113
54113430220002221
6135514430245423
712263153654025
oct1713147247127
9413414203126
10130352500311
1150311651900
122131a956873
13c3a4c24ab7
146448227715
1535cdc930c6
hex1e599d4e57

130352500311 has 24 divisors (see below), whose sum is σ = 191060352000. Its totient is φ = 78993111120.

The previous prime is 130352500307. The next prime is 130352500337. The reversal of 130352500311 is 113005253031.

It is not a de Polignac number, because 130352500311 - 22 = 130352500307 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130352500301) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 6052440 + ... + 6073938.

It is an arithmetic number, because the mean of its divisors is an integer number (7960848000).

Almost surely, 2130352500311 is an apocalyptic number.

130352500311 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

130352500311 is a deficient number, since it is larger than the sum of its proper divisors (60707851689).

130352500311 is a wasteful number, since it uses less digits than its factorization.

130352500311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 38227 (or 38216 counting only the distinct ones).

The product of its (nonzero) digits is 1350, while the sum is 24.

Adding to 130352500311 its reverse (113005253031), we get a palindrome (243357753342).

The spelling of 130352500311 in words is "one hundred thirty billion, three hundred fifty-two million, five hundred thousand, three hundred eleven".

Divisors: 1 3 11 33 121 363 16703 21499 50109 64497 183733 236489 551199 709467 2021063 2601379 6063189 7804137 359097797 1077293391 3950075767 11850227301 43450833437 130352500311