Base | Representation |
---|---|
bin | 11000010001111100… |
… | …01001011111111001 |
3 | 1020122110102111211122 |
4 | 30020332021133321 |
5 | 203144031131244 |
6 | 5553254035025 |
7 | 641013112004 |
oct | 141076113771 |
9 | 36573374748 |
10 | 13035411449 |
11 | 558a171615 |
12 | 2639648a75 |
13 | 12c981cb18 |
14 | 8b934653b |
15 | 5145e91ee |
hex | 308f897f9 |
13035411449 has 2 divisors, whose sum is σ = 13035411450. Its totient is φ = 13035411448.
The previous prime is 13035411439. The next prime is 13035411457. The reversal of 13035411449 is 94411453031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12994860025 + 40551424 = 113995^2 + 6368^2 .
It is a cyclic number.
It is not a de Polignac number, because 13035411449 - 212 = 13035407353 is a prime.
It is a super-3 number, since 3×130354114493 (a number of 31 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (13035411439) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6517705724 + 6517705725.
It is an arithmetic number, because the mean of its divisors is an integer number (6517705725).
Almost surely, 213035411449 is an apocalyptic number.
It is an amenable number.
13035411449 is a deficient number, since it is larger than the sum of its proper divisors (1).
13035411449 is an equidigital number, since it uses as much as digits as its factorization.
13035411449 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 25920, while the sum is 35.
The spelling of 13035411449 in words is "thirteen billion, thirty-five million, four hundred eleven thousand, four hundred forty-nine".
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