Base | Representation |
---|---|
bin | 11000010010011111… |
… | …01011000000100011 |
3 | 1020122210001220012220 |
4 | 30021033223000203 |
5 | 203201220131110 |
6 | 5553540322123 |
7 | 641100133512 |
oct | 141117530043 |
9 | 36583056186 |
10 | 13040005155 |
11 | 5591819971 |
12 | 263b0a3343 |
13 | 12ca76a9a8 |
14 | 8b9bc0679 |
15 | 514c05370 |
hex | 3093eb023 |
13040005155 has 16 divisors (see below), whose sum is σ = 20891443104. Its totient is φ = 6945524480.
The previous prime is 13040005123. The next prime is 13040005163. The reversal of 13040005155 is 55150004031.
It is not a de Polignac number, because 13040005155 - 25 = 13040005123 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 559764 + ... + 582593.
It is an arithmetic number, because the mean of its divisors is an integer number (1305715194).
Almost surely, 213040005155 is an apocalyptic number.
13040005155 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13040005155 is a deficient number, since it is larger than the sum of its proper divisors (7851437949).
13040005155 is a wasteful number, since it uses less digits than its factorization.
13040005155 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1143126.
The product of its (nonzero) digits is 1500, while the sum is 24.
Adding to 13040005155 its reverse (55150004031), we get a palindrome (68190009186).
The spelling of 13040005155 in words is "thirteen billion, forty million, five thousand, one hundred fifty-five".
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