Base | Representation |
---|---|
bin | 11101101001100101000010… |
… | …101011000000000011001011 |
3 | 122002201011210110102120020011 |
4 | 131221211002223000003023 |
5 | 114042440432341030012 |
6 | 1141201115040412351 |
7 | 36316063641035035 |
oct | 3551450253000313 |
9 | 562634713376204 |
10 | 130400620642507 |
11 | 386056578a7516 |
12 | 127606200170b7 |
13 | 579b958668ac7 |
14 | 242b5d095cc55 |
15 | 10120456db1a7 |
hex | 769942ac00cb |
130400620642507 has 2 divisors, whose sum is σ = 130400620642508. Its totient is φ = 130400620642506.
The previous prime is 130400620642477. The next prime is 130400620642571. The reversal of 130400620642507 is 705246026004031.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130400620642507 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 130400620642507.
It is not a weakly prime, because it can be changed into another prime (130400620642597) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65200310321253 + 65200310321254.
It is an arithmetic number, because the mean of its divisors is an integer number (65200310321254).
Almost surely, 2130400620642507 is an apocalyptic number.
130400620642507 is a deficient number, since it is larger than the sum of its proper divisors (1).
130400620642507 is an equidigital number, since it uses as much as digits as its factorization.
130400620642507 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 241920, while the sum is 40.
Adding to 130400620642507 its reverse (705246026004031), we get a palindrome (835646646646538).
The spelling of 130400620642507 in words is "one hundred thirty trillion, four hundred billion, six hundred twenty million, six hundred forty-two thousand, five hundred seven".
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