Base | Representation |
---|---|
bin | 11000010010100000… |
… | …00010001111011101 |
3 | 1020122210020201202102 |
4 | 30021100002033131 |
5 | 203201231202232 |
6 | 5553542334445 |
7 | 641101011116 |
oct | 141120021735 |
9 | 36583221672 |
10 | 13040100317 |
11 | 5591884412 |
12 | 263b12a425 |
13 | 12ca7a20ba |
14 | 8b9c0720d |
15 | 514c23662 |
hex | 3094023dd |
13040100317 has 4 divisors (see below), whose sum is σ = 13040587740. Its totient is φ = 13039612896.
The previous prime is 13040100289. The next prime is 13040100329. The reversal of 13040100317 is 71300104031.
It is a happy number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 10721774116 + 2318326201 = 103546^2 + 48149^2 .
It is a cyclic number.
It is not a de Polignac number, because 13040100317 - 216 = 13040034781 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13040100377) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 201098 + ... + 257915.
It is an arithmetic number, because the mean of its divisors is an integer number (3260146935).
Almost surely, 213040100317 is an apocalyptic number.
It is an amenable number.
13040100317 is a deficient number, since it is larger than the sum of its proper divisors (487423).
13040100317 is an equidigital number, since it uses as much as digits as its factorization.
13040100317 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 487422.
The product of its (nonzero) digits is 252, while the sum is 20.
Adding to 13040100317 its reverse (71300104031), we get a palindrome (84340204348).
The spelling of 13040100317 in words is "thirteen billion, forty million, one hundred thousand, three hundred seventeen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.083 sec. • engine limits •