13040113423 has 4 divisors (see below), whose sum is σ = 13174547680. Its totient is φ = 12905679168.

The previous prime is 13040113369. The next prime is 13040113439. The reversal of 13040113423 is 32431104031.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 32431104031 = 2441 ⋅13285991.

It is a cyclic number.

It is not a de Polignac number, because 13040113423 - 2²⁵ = 13006558991 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13040113394 and 13040113403.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13040113123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 67216983 + ... + 67217176.

It is an arithmetic number, because the mean of its divisors is an integer number (3293636920).

Almost surely, 2^13040113423 is an apocalyptic number.

13040113423 is a deficient number, since it is larger than the sum of its proper divisors (134434257).

13040113423 is an equidigital number, since it uses as much as digits as its factorization.

13040113423 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 134434256.

The product of its (nonzero) digits is 864, while the sum is 22.

Adding to 13040113423 its reverse (32431104031), we get a palindrome (45471217454).

The spelling of 13040113423 in words is "thirteen billion, forty million, one hundred thirteen thousand, four hundred twenty-three".