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130401233243434 = 2193431611401143
BaseRepresentation
bin11101101001100101100111…
…001011111000110100101010
3122002201020101011010220201101
4131221211213023320310222
5114042443211202242214
61141201255522512014
736316115060045416
oct3551454713706452
9562636334126641
10130401233243434
113860594168167a
121276077120560a
13579ba2555706a
14242b64c065d46
15101207e397774
hex7699672f8d2a

130401233243434 has 8 divisors (see below), whose sum is σ = 205896684068640. Its totient is φ = 61769005220556.

The previous prime is 130401233243389. The next prime is 130401233243441. The reversal of 130401233243434 is 434342332104031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×1304012332434342 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 130401233243393 and 130401233243402.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1715805700534 + ... + 1715805700609.

It is an arithmetic number, because the mean of its divisors is an integer number (25737085508580).

Almost surely, 2130401233243434 is an apocalyptic number.

130401233243434 is a deficient number, since it is larger than the sum of its proper divisors (75495450825206).

130401233243434 is a wasteful number, since it uses less digits than its factorization.

130401233243434 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3431611401164.

The product of its (nonzero) digits is 248832, while the sum is 37.

Adding to 130401233243434 its reverse (434342332104031), we get a palindrome (564743565347465).

The spelling of 130401233243434 in words is "one hundred thirty trillion, four hundred one billion, two hundred thirty-three million, two hundred forty-three thousand, four hundred thirty-four".

Divisors: 1 2 19 38 3431611401143 6863222802286 65200616621717 130401233243434