Base | Representation |
---|---|
bin | 10010111110011101001… |
… | …100010100000011000001 |
3 | 11121122212212021111221201 |
4 | 102332131030110003001 |
5 | 132331104124411231 |
6 | 2435015514021201 |
7 | 163132433006005 |
oct | 22763514240301 |
9 | 4548785244851 |
10 | 1304012341441 |
11 | 463034a75757 |
12 | 190887117801 |
13 | 95c7744a384 |
14 | 471863d2705 |
15 | 23dc12d7161 |
hex | 12f9d3140c1 |
1304012341441 has 2 divisors, whose sum is σ = 1304012341442. Its totient is φ = 1304012341440.
The previous prime is 1304012341433. The next prime is 1304012341451. The reversal of 1304012341441 is 1441432104031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1175264137216 + 128748204225 = 1084096^2 + 358815^2 .
It is a cyclic number.
It is not a de Polignac number, because 1304012341441 - 23 = 1304012341433 is a prime.
It is not a weakly prime, because it can be changed into another prime (1304012341451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652006170720 + 652006170721.
It is an arithmetic number, because the mean of its divisors is an integer number (652006170721).
Almost surely, 21304012341441 is an apocalyptic number.
It is an amenable number.
1304012341441 is a deficient number, since it is larger than the sum of its proper divisors (1).
1304012341441 is an equidigital number, since it uses as much as digits as its factorization.
1304012341441 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4608, while the sum is 28.
Adding to 1304012341441 its reverse (1441432104031), we get a palindrome (2745444445472).
The spelling of 1304012341441 in words is "one trillion, three hundred four billion, twelve million, three hundred forty-one thousand, four hundred forty-one".
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