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130402021440000 = 29354985113789
BaseRepresentation
bin11101101001100110010110…
…001010100111101000000000
3122002201022102002021110010210
4131221212112022213220000
5114043001314442040000
61141201510040354120
736316143440441532
oct3551462612475000
9562638362243123
10130402021440000
11386062065903a2
1212760951175940
13579bb1c93656b
14242b6c49db852
1510120c868c350
hex7699962a7a00

130402021440000 has 400 divisors, whose sum is σ = 434185512536160. Its totient is φ = 34767820800000.

The previous prime is 130402021439923. The next prime is 130402021440011. The reversal of 130402021440000 is 44120204031.

It is a tau number, because it is divible by the number of its divisors (400).

It is an unprimeable number.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 9456953106 + ... + 9456966894.

Almost surely, 2130402021440000 is an apocalyptic number.

130402021440000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 130402021440000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (217092756268080).

130402021440000 is an abundant number, since it is smaller than the sum of its proper divisors (303783491096160).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130402021440000 is an frugal number, since it uses more digits than its factorization.

130402021440000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 23681 (or 23650 counting only the distinct ones).

The product of its (nonzero) digits is 768, while the sum is 21.

Adding to 130402021440000 its reverse (44120204031), we get a palindrome (130446141644031).

The spelling of 130402021440000 in words is "one hundred thirty trillion, four hundred two billion, twenty-one million, four hundred forty thousand".