Base | Representation |
---|---|
bin | 1011110111000010101010… |
… | …0010111000111111000011 |
3 | 1201011122010100210220100110 |
4 | 2331300222202320333003 |
5 | 3202122400013000120 |
6 | 43422333453322403 |
7 | 2514061111246641 |
oct | 275605242707703 |
9 | 51148110726313 |
10 | 13040234500035 |
11 | 4178372465116 |
12 | 1567350196403 |
13 | 7378c54b42a2 |
14 | 3312177d6191 |
15 | 179316a402e0 |
hex | bdc2a8b8fc3 |
13040234500035 has 24 divisors (see below), whose sum is σ = 20886879072240. Its totient is φ = 6947298515968.
The previous prime is 13040234500021. The next prime is 13040234500037. The reversal of 13040234500035 is 53000543204031.
It is not a de Polignac number, because 13040234500035 - 24 = 13040234500019 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13040234499975 and 13040234500011.
It is not an unprimeable number, because it can be changed into a prime (13040234500037) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 12441961 + ... + 13449269.
It is an arithmetic number, because the mean of its divisors is an integer number (870286628010).
Almost surely, 213040234500035 is an apocalyptic number.
13040234500035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13040234500035 is a deficient number, since it is larger than the sum of its proper divisors (7846644572205).
13040234500035 is an frugal number, since it uses more digits than its factorization.
13040234500035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1009175 (or 1008246 counting only the distinct ones).
The product of its (nonzero) digits is 21600, while the sum is 30.
Adding to 13040234500035 its reverse (53000543204031), we get a palindrome (66040777704066).
The spelling of 13040234500035 in words is "thirteen trillion, forty billion, two hundred thirty-four million, five hundred thousand, thirty-five".
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