Base | Representation |
---|---|
bin | 11000010010100001… |
… | …01011100101010011 |
3 | 1020122210120100001001 |
4 | 30021100223211103 |
5 | 203201302112101 |
6 | 5553550122431 |
7 | 641102314603 |
oct | 141120534523 |
9 | 36583510031 |
10 | 13040269651 |
11 | 559198a662 |
12 | 263b1b0417 |
13 | 12ca8311b6 |
14 | 8b9c4cc03 |
15 | 514c58901 |
hex | 30942b953 |
13040269651 has 2 divisors, whose sum is σ = 13040269652. Its totient is φ = 13040269650.
The previous prime is 13040269579. The next prime is 13040269667. The reversal of 13040269651 is 15696204031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13040269651 - 225 = 13006715219 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13040269651.
It is not a weakly prime, because it can be changed into another prime (13040269351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6520134825 + 6520134826.
It is an arithmetic number, because the mean of its divisors is an integer number (6520134826).
Almost surely, 213040269651 is an apocalyptic number.
13040269651 is a deficient number, since it is larger than the sum of its proper divisors (1).
13040269651 is an equidigital number, since it uses as much as digits as its factorization.
13040269651 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 38880, while the sum is 37.
The spelling of 13040269651 in words is "thirteen billion, forty million, two hundred sixty-nine thousand, six hundred fifty-one".
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