Search a number
-
+
13040432555041 is a prime number
BaseRepresentation
bin1011110111000011011001…
…0110011010010000100001
31201011122122011111010202001
42331300312112122100201
53202123301213230131
643422405250324001
72514066034553533
oct275606626322041
951148564433661
1013040432555041
114178464239841
1215673a6589601
1373792753a1b8
14331235c2d853
15179329113261
hexbdc3659a421

13040432555041 has 2 divisors, whose sum is σ = 13040432555042. Its totient is φ = 13040432555040.

The previous prime is 13040432555027. The next prime is 13040432555069. The reversal of 13040432555041 is 14055523404031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11716045882641 + 1324386672400 = 3422871^2 + 1150820^2 .

It is an emirp because it is prime and its reverse (14055523404031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13040432555041 - 29 = 13040432554529 is a prime.

It is not a weakly prime, because it can be changed into another prime (13040432555011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6520216277520 + 6520216277521.

It is an arithmetic number, because the mean of its divisors is an integer number (6520216277521).

Almost surely, 213040432555041 is an apocalyptic number.

It is an amenable number.

13040432555041 is a deficient number, since it is larger than the sum of its proper divisors (1).

13040432555041 is an equidigital number, since it uses as much as digits as its factorization.

13040432555041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144000, while the sum is 37.

Adding to 13040432555041 its reverse (14055523404031), we get a palindrome (27095955959072).

The spelling of 13040432555041 in words is "thirteen trillion, forty billion, four hundred thirty-two million, five hundred fifty-five thousand, forty-one".