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13040440330442 = 27931460023603
BaseRepresentation
bin1011110111000011011011…
…0100000100100011001010
31201011122122201010011120212
42331300312310010203022
53202123310211033232
643422410125121122
72514066160626410
oct275606664044312
951148581104525
1013040440330442
11417846866a598
1215673a90b91a2
13737929030325
14331236c952b0
15179329b4beb2
hexbdc36d048ca

13040440330442 has 8 divisors (see below), whose sum is σ = 22355040566496. Its totient is φ = 5588760141612.

The previous prime is 13040440330441. The next prime is 13040440330447. The reversal of 13040440330442 is 24403304404031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-4 number, since 4×130404403304424 (a number of 54 digits) contains 4444 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13040440330399 and 13040440330408.

It is not an unprimeable number, because it can be changed into a prime (13040440330441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 465730011788 + ... + 465730011815.

It is an arithmetic number, because the mean of its divisors is an integer number (2794380070812).

Almost surely, 213040440330442 is an apocalyptic number.

13040440330442 is a deficient number, since it is larger than the sum of its proper divisors (9314600236054).

13040440330442 is an equidigital number, since it uses as much as digits as its factorization.

13040440330442 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 931460023612.

The product of its (nonzero) digits is 55296, while the sum is 32.

Adding to 13040440330442 its reverse (24403304404031), we get a palindrome (37443744734473).

The spelling of 13040440330442 in words is "thirteen trillion, forty billion, four hundred forty million, three hundred thirty thousand, four hundred forty-two".

Divisors: 1 2 7 14 931460023603 1862920047206 6520220165221 13040440330442