13040443113 has 8 divisors (see below), whose sum is σ = 18410037408. Its totient is φ = 8182238784.

The previous prime is 13040443099. The next prime is 13040443121. The reversal of 13040443113 is 31134404031.

13040443113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13040443113 - 2⁶ = 13040443049 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13040443183) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 127847431 + ... + 127847532.

It is an arithmetic number, because the mean of its divisors is an integer number (2301254676).

Almost surely, 2^13040443113 is an apocalyptic number.

It is an amenable number.

13040443113 is a deficient number, since it is larger than the sum of its proper divisors (5369594295).

13040443113 is a wasteful number, since it uses less digits than its factorization.

13040443113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 255694983.

The product of its (nonzero) digits is 1728, while the sum is 24.

Adding to 13040443113 its reverse (31134404031), we get a palindrome (44174847144).

The spelling of 13040443113 in words is "thirteen billion, forty million, four hundred forty-three thousand, one hundred thirteen".