Base | Representation |
---|---|
bin | 11000010010100010… |
… | …10101111011101010 |
3 | 1020122210220010222121 |
4 | 30021101111323222 |
5 | 203201323134424 |
6 | 5553553541454 |
7 | 641103636406 |
oct | 141121257352 |
9 | 36583803877 |
10 | 13040443114 |
11 | 5591a98a16 |
12 | 263b27488a |
13 | 12ca89213a |
14 | 8b9c96106 |
15 | 514c8eee4 |
hex | 309455eea |
13040443114 has 4 divisors (see below), whose sum is σ = 19560664674. Its totient is φ = 6520221556.
The previous prime is 13040443099. The next prime is 13040443121. The reversal of 13040443114 is 41134404031.
13040443114 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 7050457089 + 5989986025 = 83967^2 + 77395^2 .
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3260110777 + ... + 3260110780.
Almost surely, 213040443114 is an apocalyptic number.
13040443114 is a deficient number, since it is larger than the sum of its proper divisors (6520221560).
13040443114 is an equidigital number, since it uses as much as digits as its factorization.
13040443114 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6520221559.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 13040443114 its reverse (41134404031), we get a palindrome (54174847145).
The spelling of 13040443114 in words is "thirteen billion, forty million, four hundred forty-three thousand, one hundred fourteen".
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