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1304052442400 = 2552172922314827
BaseRepresentation
bin10010111110011111100…
…101010010010100100000
311121122222122201212010102
4102332133211102110200
5132331144411124100
62435023505321532
7163133430604301
oct22763745222440
94548878655112
101304052442400
11463055675144
121908986362a8
1395c8284ab56
144718b8707a8
1523dc4aa8cd5
hex12f9f952520

1304052442400 has 288 divisors, whose sum is σ = 3502890800640. Its totient is φ = 471851089920.

The previous prime is 1304052442367. The next prime is 1304052442403. The reversal of 1304052442400 is 42442504031.

It is a super-3 number, since 3×13040524424003 (a number of 37 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (29).

It is not an unprimeable number, because it can be changed into a prime (1304052442403) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 87943787 + ... + 87958613.

It is an arithmetic number, because the mean of its divisors is an integer number (12162815280).

Almost surely, 21304052442400 is an apocalyptic number.

1304052442400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1304052442400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1751445400320).

1304052442400 is an abundant number, since it is smaller than the sum of its proper divisors (2198838358240).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1304052442400 is a wasteful number, since it uses less digits than its factorization.

1304052442400 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15116 (or 15103 counting only the distinct ones).

The product of its (nonzero) digits is 15360, while the sum is 29.

Adding to 1304052442400 its reverse (42442504031), we get a palindrome (1346494946431).

The spelling of 1304052442400 in words is "one trillion, three hundred four billion, fifty-two million, four hundred forty-two thousand, four hundred".