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130410132003113 is a prime number
BaseRepresentation
bin11101101001101101111001…
…100101111101100100101001
3122002202002100022201202010012
4131221231321211331210221
5114043114422243044423
61141205330530101305
736316551433210244
oct3551557145754451
9562662308652105
10130410132003113
1138609698804516
121276243541a835
13579c81304b131
14242bc53c4625b
151012400727078
hex769b7997d929

130410132003113 has 2 divisors, whose sum is σ = 130410132003114. Its totient is φ = 130410132003112.

The previous prime is 130410132003089. The next prime is 130410132003157. The reversal of 130410132003113 is 311300231014031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 116923845275689 + 13486286727424 = 10813133^2 + 3672368^2 .

It is a cyclic number.

It is not a de Polignac number, because 130410132003113 - 222 = 130410127808809 is a prime.

It is not a weakly prime, because it can be changed into another prime (130410132003013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65205066001556 + 65205066001557.

It is an arithmetic number, because the mean of its divisors is an integer number (65205066001557).

Almost surely, 2130410132003113 is an apocalyptic number.

It is an amenable number.

130410132003113 is a deficient number, since it is larger than the sum of its proper divisors (1).

130410132003113 is an equidigital number, since it uses as much as digits as its factorization.

130410132003113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 130410132003113 its reverse (311300231014031), we get a palindrome (441710363017144).

The spelling of 130410132003113 in words is "one hundred thirty trillion, four hundred ten billion, one hundred thirty-two million, three thousand, one hundred thirteen".