Base | Representation |
---|---|
bin | 11101101001101110000110… |
… | …000100111010101100010011 |
3 | 122002202002212220211110111211 |
4 | 131221232012010322230103 |
5 | 114043120334402204441 |
6 | 1141205403411120551 |
7 | 36316556555346202 |
oct | 3551560604725423 |
9 | 562662786743454 |
10 | 130410341444371 |
11 | 38609795a5586a |
12 | 127624935a3157 |
13 | 579c84755c881 |
14 | 242bc739a5239 |
15 | 1012413ce8a81 |
hex | 769b8613ab13 |
130410341444371 has 2 divisors, whose sum is σ = 130410341444372. Its totient is φ = 130410341444370.
The previous prime is 130410341444321. The next prime is 130410341444381. The reversal of 130410341444371 is 173444143014031.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130410341444371 is a prime.
It is not a weakly prime, because it can be changed into another prime (130410341444321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65205170722185 + 65205170722186.
It is an arithmetic number, because the mean of its divisors is an integer number (65205170722186).
Almost surely, 2130410341444371 is an apocalyptic number.
130410341444371 is a deficient number, since it is larger than the sum of its proper divisors (1).
130410341444371 is an equidigital number, since it uses as much as digits as its factorization.
130410341444371 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 193536, while the sum is 40.
The spelling of 130410341444371 in words is "one hundred thirty trillion, four hundred ten billion, three hundred forty-one million, four hundred forty-four thousand, three hundred seventy-one".
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