130410401521 has 2 divisors, whose sum is σ = 130410401522. Its totient is φ = 130410401520.

The previous prime is 130410401467. The next prime is 130410401573. The reversal of 130410401521 is 125104014031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 97153773025 + 33256628496 = 311695^2 + 182364^2 .

It is a cyclic number.

It is not a de Polignac number, because 130410401521 - 2¹³ = 130410393329 is a prime.

It is a super-2 number, since 2×130410401521² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 130410401492 and 130410401501.

It is not a weakly prime, because it can be changed into another prime (130410401321) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65205200760 + 65205200761.

It is an arithmetic number, because the mean of its divisors is an integer number (65205200761).

Almost surely, 2^130410401521 is an apocalyptic number.

It is an amenable number.

130410401521 is a deficient number, since it is larger than the sum of its proper divisors (1).

130410401521 is an equidigital number, since it uses as much as digits as its factorization.

130410401521 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 480, while the sum is 22.

Adding to 130410401521 its reverse (125104014031), we get a palindrome (255514415552).

The spelling of 130410401521 in words is "one hundred thirty billion, four hundred ten million, four hundred one thousand, five hundred twenty-one".