130411010441 has 2 divisors, whose sum is σ = 130411010442. Its totient is φ = 130411010440.

The previous prime is 130411010393. The next prime is 130411010447. The reversal of 130411010441 is 144010114031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 129873744400 + 537266041 = 360380^2 + 23179^2 .

It is a cyclic number.

It is not a de Polignac number, because 130411010441 - 2⁶ = 130411010377 is a prime.

It is a super-2 number, since 2×130411010441² (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (130411010447) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65205505220 + 65205505221.

It is an arithmetic number, because the mean of its divisors is an integer number (65205505221).

Almost surely, 2^130411010441 is an apocalyptic number.

It is an amenable number.

130411010441 is a deficient number, since it is larger than the sum of its proper divisors (1).

130411010441 is an equidigital number, since it uses as much as digits as its factorization.

130411010441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 192, while the sum is 20.

Adding to 130411010441 its reverse (144010114031), we get a palindrome (274421124472).

The spelling of 130411010441 in words is "one hundred thirty billion, four hundred eleven million, ten thousand, four hundred forty-one".