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1304121012457 is a prime number
BaseRepresentation
bin10010111110100011101…
…010110111000011101001
311121200011102202120120011
4102332203222313003221
5132331314434344312
62435034355131521
7163135222464064
oct22764352670351
94550142676504
101304121012457
1146309034990a
121908b75a3ba1
1395c93b08853
14471969dd8db
1523dcab00da7
hex12fa3ab70e9

1304121012457 has 2 divisors, whose sum is σ = 1304121012458. Its totient is φ = 1304121012456.

The previous prime is 1304121012379. The next prime is 1304121012479. The reversal of 1304121012457 is 7542101214031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 751508674816 + 552612337641 = 866896^2 + 743379^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1304121012457 is a prime.

It is not a weakly prime, because it can be changed into another prime (1304121012757) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652060506228 + 652060506229.

It is an arithmetic number, because the mean of its divisors is an integer number (652060506229).

Almost surely, 21304121012457 is an apocalyptic number.

It is an amenable number.

1304121012457 is a deficient number, since it is larger than the sum of its proper divisors (1).

1304121012457 is an equidigital number, since it uses as much as digits as its factorization.

1304121012457 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6720, while the sum is 31.

Adding to 1304121012457 its reverse (7542101214031), we get a palindrome (8846222226488).

The spelling of 1304121012457 in words is "one trillion, three hundred four billion, one hundred twenty-one million, twelve thousand, four hundred fifty-seven".