Base | Representation |
---|---|
bin | 111100101110100101… |
… | …1001110100101101111 |
3 | 110110121122122101010121 |
4 | 1321131023032211233 |
5 | 4114041013241221 |
6 | 135524402545411 |
7 | 12264510530620 |
oct | 1713513164557 |
9 | 413548571117 |
10 | 130412243311 |
11 | 50342347689 |
12 | 21336968267 |
13 | c3b4411a9c |
14 | 6452139a47 |
15 | 35d4144a41 |
hex | 1e5d2ce96f |
130412243311 has 8 divisors (see below), whose sum is σ = 149046303744. Its totient is φ = 111779117880.
The previous prime is 130412243287. The next prime is 130412243359. The reversal of 130412243311 is 113342214031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 130412243311 - 211 = 130412241263 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130412243911) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 96186 + ... + 519688.
It is an arithmetic number, because the mean of its divisors is an integer number (18630787968).
Almost surely, 2130412243311 is an apocalyptic number.
130412243311 is a deficient number, since it is larger than the sum of its proper divisors (18634060433).
130412243311 is an equidigital number, since it uses as much as digits as its factorization.
130412243311 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 467501.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 130412243311 its reverse (113342214031), we get a palindrome (243754457342).
The spelling of 130412243311 in words is "one hundred thirty billion, four hundred twelve million, two hundred forty-three thousand, three hundred eleven".
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