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1304124044323 is a prime number
BaseRepresentation
bin10010111110100011110…
…110011011010000100011
311121200011122110121111111
4102332203312123100203
5132331321223404243
62435034544124151
7163135260322252
oct22764366332043
94550148417444
101304124044323
1146309202a791
121908b8606657
1395c9462a859
144719718c799
1523dcaeee39d
hex12fa3d9b423

1304124044323 has 2 divisors, whose sum is σ = 1304124044324. Its totient is φ = 1304124044322.

The previous prime is 1304124044297. The next prime is 1304124044339. The reversal of 1304124044323 is 3234404214031.

It is a strong prime.

It is an emirp because it is prime and its reverse (3234404214031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1304124044323 - 217 = 1304123913251 is a prime.

It is a super-3 number, since 3×13041240443233 (a number of 37 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (1304124044383) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652062022161 + 652062022162.

It is an arithmetic number, because the mean of its divisors is an integer number (652062022162).

Almost surely, 21304124044323 is an apocalyptic number.

1304124044323 is a deficient number, since it is larger than the sum of its proper divisors (1).

1304124044323 is an equidigital number, since it uses as much as digits as its factorization.

1304124044323 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 27648, while the sum is 31.

Adding to 1304124044323 its reverse (3234404214031), we get a palindrome (4538528258354).

The spelling of 1304124044323 in words is "one trillion, three hundred four billion, one hundred twenty-four million, forty-four thousand, three hundred twenty-three".