Base | Representation |
---|---|
bin | 10010111110100011110… |
… | …110011011010000100011 |
3 | 11121200011122110121111111 |
4 | 102332203312123100203 |
5 | 132331321223404243 |
6 | 2435034544124151 |
7 | 163135260322252 |
oct | 22764366332043 |
9 | 4550148417444 |
10 | 1304124044323 |
11 | 46309202a791 |
12 | 1908b8606657 |
13 | 95c9462a859 |
14 | 4719718c799 |
15 | 23dcaeee39d |
hex | 12fa3d9b423 |
1304124044323 has 2 divisors, whose sum is σ = 1304124044324. Its totient is φ = 1304124044322.
The previous prime is 1304124044297. The next prime is 1304124044339. The reversal of 1304124044323 is 3234404214031.
It is a strong prime.
It is an emirp because it is prime and its reverse (3234404214031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1304124044323 - 217 = 1304123913251 is a prime.
It is a super-3 number, since 3×13041240443233 (a number of 37 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (1304124044383) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652062022161 + 652062022162.
It is an arithmetic number, because the mean of its divisors is an integer number (652062022162).
Almost surely, 21304124044323 is an apocalyptic number.
1304124044323 is a deficient number, since it is larger than the sum of its proper divisors (1).
1304124044323 is an equidigital number, since it uses as much as digits as its factorization.
1304124044323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 27648, while the sum is 31.
Adding to 1304124044323 its reverse (3234404214031), we get a palindrome (4538528258354).
The spelling of 1304124044323 in words is "one trillion, three hundred four billion, one hundred twenty-four million, forty-four thousand, three hundred twenty-three".
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