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130412537 is a prime number
BaseRepresentation
bin1111100010111…
…10111111111001
3100002101122100222
413301132333321
5231341200122
620535105425
73142326323
oct761367771
9302348328
10130412537
1167683962
1237812275
13210314a8
141346a613
15b6b0b42
hex7c5eff9

130412537 has 2 divisors, whose sum is σ = 130412538. Its totient is φ = 130412536.

The previous prime is 130412497. The next prime is 130412543. The reversal of 130412537 is 735214031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 82373776 + 48038761 = 9076^2 + 6931^2 .

It is a cyclic number.

It is not a de Polignac number, because 130412537 - 26 = 130412473 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (130411537) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65206268 + 65206269.

It is an arithmetic number, because the mean of its divisors is an integer number (65206269).

Almost surely, 2130412537 is an apocalyptic number.

It is an amenable number.

130412537 is a deficient number, since it is larger than the sum of its proper divisors (1).

130412537 is an equidigital number, since it uses as much as digits as its factorization.

130412537 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2520, while the sum is 26.

The square root of 130412537 is about 11419.8308656477. The cubic root of 130412537 is about 507.1149896024.

Adding to 130412537 its reverse (735214031), we get a palindrome (865626568).

The spelling of 130412537 in words is "one hundred thirty million, four hundred twelve thousand, five hundred thirty-seven".