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130413223353937 is a prime number
BaseRepresentation
bin11101101001110000110001…
…110110100001111001010001
3122002202101022202122122020011
4131221300301312201321101
5114043142240134311222
61141211001400314521
736320021151232666
oct3551606166417121
9562671282578204
10130413223353937
113860aa34799107
1212762b58772a41
13579cbb66383c4
14242c06862ba6d
151012531d12c77
hex769c31da1e51

130413223353937 has 2 divisors, whose sum is σ = 130413223353938. Its totient is φ = 130413223353936.

The previous prime is 130413223353913. The next prime is 130413223353949. The reversal of 130413223353937 is 739353322314031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 129803206120641 + 610017233296 = 11393121^2 + 781036^2 .

It is a cyclic number.

It is not a de Polignac number, because 130413223353937 - 223 = 130413214965329 is a prime.

It is not a weakly prime, because it can be changed into another prime (130413223353997) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65206611676968 + 65206611676969.

It is an arithmetic number, because the mean of its divisors is an integer number (65206611676969).

Almost surely, 2130413223353937 is an apocalyptic number.

It is an amenable number.

130413223353937 is a deficient number, since it is larger than the sum of its proper divisors (1).

130413223353937 is an equidigital number, since it uses as much as digits as its factorization.

130413223353937 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3674160, while the sum is 49.

Adding to 130413223353937 its reverse (739353322314031), we get a palindrome (869766545667968).

The spelling of 130413223353937 in words is "one hundred thirty trillion, four hundred thirteen billion, two hundred twenty-three million, three hundred fifty-three thousand, nine hundred thirty-seven".