Base | Representation |
---|---|
bin | 11101101001110000110001… |
… | …110110100001111001010001 |
3 | 122002202101022202122122020011 |
4 | 131221300301312201321101 |
5 | 114043142240134311222 |
6 | 1141211001400314521 |
7 | 36320021151232666 |
oct | 3551606166417121 |
9 | 562671282578204 |
10 | 130413223353937 |
11 | 3860aa34799107 |
12 | 12762b58772a41 |
13 | 579cbb66383c4 |
14 | 242c06862ba6d |
15 | 1012531d12c77 |
hex | 769c31da1e51 |
130413223353937 has 2 divisors, whose sum is σ = 130413223353938. Its totient is φ = 130413223353936.
The previous prime is 130413223353913. The next prime is 130413223353949. The reversal of 130413223353937 is 739353322314031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 129803206120641 + 610017233296 = 11393121^2 + 781036^2 .
It is a cyclic number.
It is not a de Polignac number, because 130413223353937 - 223 = 130413214965329 is a prime.
It is not a weakly prime, because it can be changed into another prime (130413223353997) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65206611676968 + 65206611676969.
It is an arithmetic number, because the mean of its divisors is an integer number (65206611676969).
Almost surely, 2130413223353937 is an apocalyptic number.
It is an amenable number.
130413223353937 is a deficient number, since it is larger than the sum of its proper divisors (1).
130413223353937 is an equidigital number, since it uses as much as digits as its factorization.
130413223353937 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3674160, while the sum is 49.
Adding to 130413223353937 its reverse (739353322314031), we get a palindrome (869766545667968).
The spelling of 130413223353937 in words is "one hundred thirty trillion, four hundred thirteen billion, two hundred twenty-three million, three hundred fifty-three thousand, nine hundred thirty-seven".
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