Search a number
-
+
130415162561 is a prime number
BaseRepresentation
bin111100101110101011…
…0010111010011000001
3110110121212010200120222
41321131112113103001
54114042240200221
6135524545312425
712264544406555
oct1713526272301
9413555120528
10130415162561
1150343a60992
1221337935715
13c3b4bc4758
146452699865
1535d451e9ab
hex1e5d5974c1

130415162561 has 2 divisors, whose sum is σ = 130415162562. Its totient is φ = 130415162560.

The previous prime is 130415162509. The next prime is 130415162587. The reversal of 130415162561 is 165261514031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 129963855025 + 451307536 = 360505^2 + 21244^2 .

It is a cyclic number.

It is not a de Polignac number, because 130415162561 - 230 = 129341420737 is a prime.

It is a super-2 number, since 2×1304151625612 (a number of 23 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (130415162861) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65207581280 + 65207581281.

It is an arithmetic number, because the mean of its divisors is an integer number (65207581281).

Almost surely, 2130415162561 is an apocalyptic number.

It is an amenable number.

130415162561 is a deficient number, since it is larger than the sum of its proper divisors (1).

130415162561 is an equidigital number, since it uses as much as digits as its factorization.

130415162561 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 21600, while the sum is 35.

Adding to 130415162561 its reverse (165261514031), we get a palindrome (295676676592).

The spelling of 130415162561 in words is "one hundred thirty billion, four hundred fifteen million, one hundred sixty-two thousand, five hundred sixty-one".