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13041998726400 = 2832527197323321
BaseRepresentation
bin1011110111001001001110…
…1100111000010100000000
31201011210200022111212221200
42331302103230320110000
53202140003133221100
643423224515021200
72514152613031020
oct275622354702400
951153608455850
1013041998726400
114179098305536
121567762b9a800
13737b16b5a407
14331343c39a80
151793bb87de00
hexbdc93b38500

13041998726400 has 1296 divisors, whose sum is σ = 56864790003840. Its totient is φ = 2785325875200.

The previous prime is 13041998726363. The next prime is 13041998726411. The reversal of 13041998726400 is 462789914031.

13041998726400 is a `hidden beast` number, since 1 + 30 + 41 + 99 + 87 + 2 + 6 + 400 = 666.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 143 ways as a sum of consecutive naturals, for example, 559226740 + ... + 559250060.

Almost surely, 213041998726400 is an apocalyptic number.

13041998726400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13041998726400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (28432395001920).

13041998726400 is an abundant number, since it is smaller than the sum of its proper divisors (43822791277440).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13041998726400 is a wasteful number, since it uses less digits than its factorization.

13041998726400 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 23452 (or 23430 counting only the distinct ones).

The product of its (nonzero) digits is 2612736, while the sum is 54.

The spelling of 13041998726400 in words is "thirteen trillion, forty-one billion, nine hundred ninety-eight million, seven hundred twenty-six thousand, four hundred".