Base | Representation |
---|---|
bin | 111100101110110100… |
… | …0110100111011100111 |
3 | 110110122012020120210021 |
4 | 1321131220310323213 |
5 | 4114100010040120 |
6 | 135525241140011 |
7 | 12264633505354 |
oct | 1713550647347 |
9 | 413565216707 |
10 | 130420002535 |
11 | 50346767269 |
12 | 2133948a607 |
13 | c3b5bca744 |
14 | 645319962b |
15 | 35d4b78aaa |
hex | 1e5da34ee7 |
130420002535 has 8 divisors (see below), whose sum is σ = 165710120976. Its totient is φ = 98198590080.
The previous prime is 130420002523. The next prime is 130420002541. The reversal of 130420002535 is 535200024031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 130420002535 - 213 = 130419994343 is a prime.
It is a super-2 number, since 2×1304200025352 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 767176401 + ... + 767176570.
It is an arithmetic number, because the mean of its divisors is an integer number (20713765122).
Almost surely, 2130420002535 is an apocalyptic number.
130420002535 is a deficient number, since it is larger than the sum of its proper divisors (35290118441).
130420002535 is a wasteful number, since it uses less digits than its factorization.
130420002535 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1534352993.
The product of its (nonzero) digits is 3600, while the sum is 25.
Adding to 130420002535 its reverse (535200024031), we get a palindrome (665620026566).
The spelling of 130420002535 in words is "one hundred thirty billion, four hundred twenty million, two thousand, five hundred thirty-five".
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