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130420245030232 = 2368323869005313
BaseRepresentation
bin11101101001110111010100…
…011000000110010101011000
3122002210001110010011202022011
4131221313110120012111120
5114043301130211431412
61141214122231235304
736320360152422313
oct3551672430062530
9562701403152264
10130420245030232
1138612a082a8473
1212764398218b34
1357a0765290751
14242c532dcb97a
1510127e34ae7a7
hex769dd4606558

130420245030232 has 16 divisors (see below), whose sum is σ = 244895994521640. Its totient is φ = 65114646491136.

The previous prime is 130420245030227. The next prime is 130420245030247. The reversal of 130420245030232 is 232030542024031.

It is a junction number, because it is equal to n+sod(n) for n = 130420245030194 and 130420245030203.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11934497193 + ... + 11934508120.

Almost surely, 2130420245030232 is an apocalyptic number.

It is an amenable number.

130420245030232 is a deficient number, since it is larger than the sum of its proper divisors (114475749491408).

130420245030232 is a wasteful number, since it uses less digits than its factorization.

130420245030232 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 23869006002 (or 23869005998 counting only the distinct ones).

The product of its (nonzero) digits is 34560, while the sum is 31.

Adding to 130420245030232 its reverse (232030542024031), we get a palindrome (362450787054263).

The spelling of 130420245030232 in words is "one hundred thirty trillion, four hundred twenty billion, two hundred forty-five million, thirty thousand, two hundred thirty-two".

Divisors: 1 2 4 8 683 1366 2732 5464 23869005313 47738010626 95476021252 190952042504 16302530628779 32605061257558 65210122515116 130420245030232