Base | Representation |
---|---|
bin | 11101101001111000010011… |
… | …010010000001110010010000 |
3 | 122002210011011200001021001012 |
4 | 131221320103102001302100 |
5 | 114043310310400401334 |
6 | 1141214415051430052 |
7 | 36320425256066666 |
oct | 3551702322016220 |
9 | 562704150037035 |
10 | 130421300403344 |
11 | 386133aa001955 |
12 | 12764631755328 |
13 | 57a08a2b17892 |
14 | 242c5d3230c36 |
15 | 1012855e7c9ce |
hex | 769e13481c90 |
130421300403344 has 20 divisors (see below), whose sum is σ = 252691449542124. Its totient is φ = 65210603747328.
The previous prime is 130421300403313. The next prime is 130421300403481. The reversal of 130421300403344 is 443304003124031.
It can be written as a sum of positive squares in 2 ways, for example, as 54771663020944 + 75649637382400 = 7400788^2 + 8697680^2 .
It is a self number, because there is not a number n which added to its sum of digits gives 130421300403344.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 36296924 + ... + 39727940.
Almost surely, 2130421300403344 is an apocalyptic number.
It is an amenable number.
130421300403344 is a deficient number, since it is larger than the sum of its proper divisors (122270149138780).
130421300403344 is a wasteful number, since it uses less digits than its factorization.
130421300403344 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5806802 (or 5806796 counting only the distinct ones).
The product of its (nonzero) digits is 41472, while the sum is 32.
Adding to 130421300403344 its reverse (443304003124031), we get a palindrome (573725303527375).
The spelling of 130421300403344 in words is "one hundred thirty trillion, four hundred twenty-one billion, three hundred million, four hundred three thousand, three hundred forty-four".
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