Base | Representation |
---|---|
bin | 11101101001111001111111… |
… | …111000100000110011000011 |
3 | 122002210022212122111212100022 |
4 | 131221321333320200303003 |
5 | 114043323023320244141 |
6 | 1141215315540044055 |
7 | 36320521362060323 |
oct | 3551717770406303 |
9 | 562708778455308 |
10 | 130423122431171 |
11 | 38614154541379 |
12 | 12764a5b99362b |
13 | 57a0b0344b05b |
14 | 242c7271dd283 |
15 | 1012910dd7b4b |
hex | 769e7fe20cc3 |
130423122431171 has 2 divisors, whose sum is σ = 130423122431172. Its totient is φ = 130423122431170.
The previous prime is 130423122431111. The next prime is 130423122431221. The reversal of 130423122431171 is 171134221324031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130423122431171 - 210 = 130423122430147 is a prime.
It is not a weakly prime, because it can be changed into another prime (130423122431101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65211561215585 + 65211561215586.
It is an arithmetic number, because the mean of its divisors is an integer number (65211561215586).
Almost surely, 2130423122431171 is an apocalyptic number.
130423122431171 is a deficient number, since it is larger than the sum of its proper divisors (1).
130423122431171 is an equidigital number, since it uses as much as digits as its factorization.
130423122431171 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24192, while the sum is 35.
The spelling of 130423122431171 in words is "one hundred thirty trillion, four hundred twenty-three billion, one hundred twenty-two million, four hundred thirty-one thousand, one hundred seventy-one".
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