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130423144313120 = 255194122911633929
BaseRepresentation
bin11101101001111010000001…
…001011111111000100100000
3122002210022221011200120201212
4131221322001023333010200
5114043323044421004440
61141215322041045252
736320522046055151
oct3551720113770440
9562708834616655
10130423144313120
113861416592762a
1212764a67186828
1357a0b07b3cc59
14242c72a097928
151012912cab465
hex769e812ff120

130423144313120 has 384 divisors, whose sum is σ = 334075365792000. Its totient is φ = 47954009456640.

The previous prime is 130423144312969. The next prime is 130423144313123. The reversal of 130423144313120 is 21313441324031.

It is a Harshad number since it is a multiple of its sum of digits (32).

It is not an unprimeable number, because it can be changed into a prime (130423144313123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 33194995316 + ... + 33194999244.

It is an arithmetic number, because the mean of its divisors is an integer number (869987931750).

Almost surely, 2130423144313120 is an apocalyptic number.

130423144313120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 130423144313120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (167037682896000).

130423144313120 is an abundant number, since it is smaller than the sum of its proper divisors (203652221478880).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130423144313120 is a wasteful number, since it uses less digits than its factorization.

130423144313120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5396 (or 5388 counting only the distinct ones).

The product of its (nonzero) digits is 20736, while the sum is 32.

Adding to 130423144313120 its reverse (21313441324031), we get a palindrome (151736585637151).

The spelling of 130423144313120 in words is "one hundred thirty trillion, four hundred twenty-three billion, one hundred forty-four million, three hundred thirteen thousand, one hundred twenty".