13042343321341 has 4 divisors (see below), whose sum is σ = 13042351804284. Its totient is φ = 13042334838400.

The previous prime is 13042343321323. The next prime is 13042343321351. The reversal of 13042343321341 is 14312334324031.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 10113487589241 + 2928855732100 = 3180171^2 + 1711390^2 .

It is a cyclic number.

It is not a de Polignac number, because 13042343321341 - 2⁹ = 13042343320829 is a prime.

It is a super-3 number, since 3×13042343321341³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13042343321297 and 13042343321306.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13042343321311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1215790 + ... + 5250031.

It is an arithmetic number, because the mean of its divisors is an integer number (3260587951071).

Almost surely, 2^{13042343321341} is an apocalyptic number.

It is an amenable number.

13042343321341 is a deficient number, since it is larger than the sum of its proper divisors (8482943).

13042343321341 is an equidigital number, since it uses as much as digits as its factorization.

13042343321341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8482942.

The product of its (nonzero) digits is 62208, while the sum is 34.

Adding to 13042343321341 its reverse (14312334324031), we get a palindrome (27354677645372).

The spelling of 13042343321341 in words is "thirteen trillion, forty-two billion, three hundred forty-three million, three hundred twenty-one thousand, three hundred forty-one".