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1304240442313 is a prime number
BaseRepresentation
bin10010111110101010110…
…010011100101111001001
311121200110202111020112011
4102332222302130233021
5132332041023123223
62435054303015521
7163141202562064
oct22765262345711
94550422436464
101304240442313
11463141801276
1219092b59a5a1
1395cb27930c3
14471a880b8db
1523dd634280d
hex12faac9cbc9

1304240442313 has 2 divisors, whose sum is σ = 1304240442314. Its totient is φ = 1304240442312.

The previous prime is 1304240442299. The next prime is 1304240442343. The reversal of 1304240442313 is 3132440424031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 754999374649 + 549241067664 = 868907^2 + 741108^2 .

It is an emirp because it is prime and its reverse (3132440424031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1304240442313 - 213 = 1304240434121 is a prime.

It is not a weakly prime, because it can be changed into another prime (1304240442343) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652120221156 + 652120221157.

It is an arithmetic number, because the mean of its divisors is an integer number (652120221157).

Almost surely, 21304240442313 is an apocalyptic number.

It is an amenable number.

1304240442313 is a deficient number, since it is larger than the sum of its proper divisors (1).

1304240442313 is an equidigital number, since it uses as much as digits as its factorization.

1304240442313 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 27648, while the sum is 31.

Adding to 1304240442313 its reverse (3132440424031), we get a palindrome (4436680866344).

The spelling of 1304240442313 in words is "one trillion, three hundred four billion, two hundred forty million, four hundred forty-two thousand, three hundred thirteen".