Base | Representation |
---|---|
bin | 111100101110111100… |
… | …0100111100100110011 |
3 | 110110122111000220020122 |
4 | 1321131320213210303 |
5 | 4114102040022011 |
6 | 135525510000455 |
7 | 12265013626223 |
oct | 1713570474463 |
9 | 413574026218 |
10 | 130424142131 |
11 | 50349034418 |
12 | 2133a94612b |
13 | c3b6a199ca |
14 | 6453956083 |
15 | 35d51e53db |
hex | 1e5de27933 |
130424142131 has 2 divisors, whose sum is σ = 130424142132. Its totient is φ = 130424142130.
The previous prime is 130424142113. The next prime is 130424142139. The reversal of 130424142131 is 131241424031.
Together with previous prime (130424142113) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130424142131 is a prime.
It is a super-2 number, since 2×1304241421312 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 130424142131.
It is not a weakly prime, because it can be changed into another prime (130424142139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65212071065 + 65212071066.
It is an arithmetic number, because the mean of its divisors is an integer number (65212071066).
Almost surely, 2130424142131 is an apocalyptic number.
130424142131 is a deficient number, since it is larger than the sum of its proper divisors (1).
130424142131 is an equidigital number, since it uses as much as digits as its factorization.
130424142131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 26.
Adding to 130424142131 its reverse (131241424031), we get a palindrome (261665566162).
The spelling of 130424142131 in words is "one hundred thirty billion, four hundred twenty-four million, one hundred forty-two thousand, one hundred thirty-one".
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