130424543335 has 4 divisors (see below), whose sum is σ = 156509452008. Its totient is φ = 104339634664.

The previous prime is 130424543299. The next prime is 130424543339. The reversal of 130424543335 is 533345424031.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 533345424031 = 7 ⋅76192203433.

It is a cyclic number.

It is not a de Polignac number, because 130424543335 - 2³⁵ = 96064804967 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130424543294 and 130424543303.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130424543339) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13042454329 + ... + 13042454338.

It is an arithmetic number, because the mean of its divisors is an integer number (39127363002).

Almost surely, 2^130424543335 is an apocalyptic number.

130424543335 is a deficient number, since it is larger than the sum of its proper divisors (26084908673).

130424543335 is an equidigital number, since it uses as much as digits as its factorization.

130424543335 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26084908672.

The product of its (nonzero) digits is 259200, while the sum is 37.

Adding to 130424543335 its reverse (533345424031), we get a palindrome (663769967366).

The spelling of 130424543335 in words is "one hundred thirty billion, four hundred twenty-four million, five hundred forty-three thousand, three hundred thirty-five".