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13043044153 is a prime number
BaseRepresentation
bin11000010010110110…
…10000111100111001
31020122222210021221101
430021123100330321
5203203004403103
65554125411401
7641135021536
oct141133207471
936588707841
1013043044153
115593505137
122640109b61
1312cb293009
148ba371d8d
15515105a1d
hex3096d0f39

13043044153 has 2 divisors, whose sum is σ = 13043044154. Its totient is φ = 13043044152.

The previous prime is 13043044139. The next prime is 13043044193. The reversal of 13043044153 is 35144034031.

13043044153 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6599450169 + 6443593984 = 81237^2 + 80272^2 .

It is a cyclic number.

It is not a de Polignac number, because 13043044153 - 25 = 13043044121 is a prime.

It is not a weakly prime, because it can be changed into another prime (13043044123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6521522076 + 6521522077.

It is an arithmetic number, because the mean of its divisors is an integer number (6521522077).

Almost surely, 213043044153 is an apocalyptic number.

It is an amenable number.

13043044153 is a deficient number, since it is larger than the sum of its proper divisors (1).

13043044153 is an equidigital number, since it uses as much as digits as its factorization.

13043044153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8640, while the sum is 28.

Adding to 13043044153 its reverse (35144034031), we get a palindrome (48187078184).

The spelling of 13043044153 in words is "thirteen billion, forty-three million, forty-four thousand, one hundred fifty-three".